AMC8 2011
AMC8 2011 · Q8
AMC8 2011 · Q8. It mainly tests Basic counting (rules of product/sum), Casework.
Bag A contains three chips labeled 1, 3, and 5. Bag B contains three chips labeled 2, 4, and 6. If one chip is drawn from each bag, how many different values are possible for the sum of the two numbers on the chips?
袋A包含三个标签为1、3和5的筹码。袋B包含三个标签为2、4和6的筹码。如果从每个袋中抽取一个筹码，两筹码上数字之和可能有多少种不同的值？
(A)
4
4
(B)
5
5
(C)
6
6
(D)
7
7
(E)
9
9
Answer
Correct choice: (B)
正确答案：（B）
Solution
By adding a number from Bag A and a number from Bag B together, the values we can get are $3, 5, 7, 5, 7, 9, 7, 9, 11.$ Therefore the number of different values is $\boxed{\textbf{(B)}\ 5}$.
将袋A的一个数与袋B的一个数相加，可能得到的值为$3, 5, 7, 5, 7, 9, 7, 9, 11$。因此不同值的数量为$\boxed{\textbf{(B)}\ 5}$。
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