AMC8 1996

AMC8 1996 · Q6

AMC8 1996 · Q6. It mainly tests Fractions, Casework.

What is the smallest result that can be obtained by the following process? • Choose three different numbers from the set $\{3, 5, 7, 11, 13, 17\}$. • Add two of these numbers. • Multiply their sum by the third number.

通过以下过程能得到的最小结果是多少？ • 从集合 $\{3, 5, 7, 11, 13, 17\}$ 中选择三个不同的数。 • 将其中两个数相加。 • 将它们的和乘以第三个数。

(A) 15 15

(B) 30 30

(D) 50 50

(E) 56 56

Answer

Correct choice: (C)

正确答案：（C）

Solution

Answer (C): To obtain the smallest result, use the three smallest numbers. This yields three choices: $3(5+7)=36,\quad 5(3+7)=50,\quad 7(3+5)=56.$ Thus $36$ is the smallest result.

答案（C）：要得到最小的结果，使用三个最小的数。这样有三种选择： $3(5+7)=36,\quad 5(3+7)=50,\quad 7(3+5)=56.$ 因此，$36$ 是最小的结果。

Topics