AMC8 1993

AMC8 1993 · Q16

AMC8 1993 · Q16. It mainly tests Fractions.

\frac{1}{1 + \frac{1}{2 + \frac{1}{3}}} =

(A) \frac{1}{6} \frac{1}{6}

(B) \frac{3}{10} \frac{3}{10}

(D) \frac{5}{6} \frac{5}{6}

(E) \frac{10}{3} \frac{10}{3}

Answer

Correct choice: (C)

正确答案：（C）

Solution

Answer (C): Using the common denominators and simplifying yield $\dfrac{1}{1+\dfrac{1}{2+\dfrac{1}{3}}}=\dfrac{1}{1+\dfrac{1}{\dfrac{7}{3}}}=\dfrac{1}{1+\dfrac{3}{7}}=\dfrac{1}{\dfrac{10}{7}}=\dfrac{7}{10}.$

答案（C）：使用公分母并化简得到 $\dfrac{1}{1+\dfrac{1}{2+\dfrac{1}{3}}}=\dfrac{1}{1+\dfrac{1}{\dfrac{7}{3}}}=\dfrac{1}{1+\dfrac{3}{7}}=\dfrac{1}{\dfrac{10}{7}}=\dfrac{7}{10}.$

Topics

AR.001 Fractions