AMC8 1990

AMC8 1990 · Q1

AMC8 1990 · Q1. It mainly tests Money / coins, Casework.

What is the smallest sum of two 3-digit numbers that can be obtained by placing each of the six digits 4, 5, 6, 7, 8, 9 in one of the six boxes in this addition problem?

通过将六个数字4、5、6、7、8、9各放置在该加法题的六个方框中，能得到的最小两位3位数之和是多少？

(A) 947 947

(B) 1037 1037

(D) 1056 1056

(E) 1245 1245

Answer

Correct choice: (C)

正确答案：（C）

Solution

In the smallest such sum, the two smallest digits are in the hundred’s places, the next two digits in the ten’s places and the two largest digits are in the one’s places. One example is $468 + 579 = 1047$.

在这样的最小和中，两位最小的数字位于百位处，接下来两位的数字位于十位处，两位最大的数字位于个位处。一个例子是 $468 + 579 = 1047$。

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