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AMC10 2017 A

AMC10 2017 A · Q2

AMC10 2017 A · Q2. It mainly tests Money / coins, Casework.

Pablo buys popsicles for his friends. The store sells single popsicles for $1 each, 3-popsicle boxes for $2, and 5-popsicle boxes for $3. What is the greatest number of popsicles that Pablo can buy with $8?
Pablo 为他的朋友们买冰棍。商店单卖冰棍每支 1 美元,3 支装盒子 2 美元,5 支装盒子 3 美元。Pablo 用 8 美元能买到最多多少支冰棍?
(A) 8 8
(B) 11 11
(C) 12 12
(D) 13 13
(E) 15 15
Answer
Correct choice: (D)
正确答案:(D)
Solution
Answer (D): The cheapest popsicles cost \$3.00 ÷ 5 = \$0.60 each. Because 14 · \$0.60 = \$8.40 and Pablo has just \$8, he could not pay for 14 popsicles even if he were allowed to buy partial boxes. The best he can hope for is 13 popsicles, and he can achieve that by buying two 5-popsicle boxes (for \$6) and one 3-popsicle box (for \$2).
答案(D):最便宜的冰棒每支价格为 \$3.00 ÷ 5 = \$0.60。因为 14 · \$0.60 = \$8.40,而 Pablo 只有 \$8,所以即使允许购买不完整的盒装,他也买不起 14 支冰棒。他最多只能买到 13 支,可以通过购买两盒 5 支装(\$6)和一盒 3 支装(\$2)来实现。
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