/

AMC12 2020 B

AMC12 2020 B · Q15

AMC12 2020 B · Q15. It mainly tests Combinations, Casework.

There are 10 people standing equally spaced around a circle. Each person knows exactly 3 of the other 9 people: the 2 people standing next to her or him, as well as the person directly across the circle. How many ways are there for the 10 people to split up into 5 pairs so that the members of each pair know each other?
有10个人等间距地站在一个圆周上。每人恰好认识其他9人中的3人:站在他或她旁边的2个人,以及圆周正对面的人。有多少种方法让这10个人分成5对,使得每对成员互相认识?
(A) 11 11
(B) 12 12
(C) 13 13
(D) 14 14
(E) 15 15
Answer
Correct choice: (C)
正确答案:(C)
Solution
Answer (C): This problem can be modeled by a regular decagon with the 5 diagonals connecting each point to the point opposite to it. A line segment between two vertices indicates that the people represented by those vertices know each other. See the figure below. The required pairings are then sets of 5 of the 15 line segments in this figure such that no 2 line segments in a set share an endpoint. (This is known as a perfect matching in graph theory.) The number of pairings can be counted by focusing on the number of diagonals used in the pairing. • There is 1 pairing using all 5 diagonals, and any pairing that includes 4 of the diagonals must use all of them. • Suppose a pairing uses exactly 3 diagonals. If 3 of the endpoints of these diagonals are consecutive points on the decagon, then a pairing can be formed by including sides of the decagon as the other 2 segments. There are 5 different pairings of this form. On the other hand, any pairing that includes 3 of the diagonals whose endpoints are not consecutive points on the decagon must use all the diagonals. • There are no pairings using exactly 2 of the diagonals, because any pairing that includes 2 of the diagonals will force at least 3 of the diagonals to be used. • If a pairing uses exactly 1 diagonal, then the rest of the pairing is uniquely determined. There are 5 different pairings of this form. • If a pairing uses no diagonals, then it must use nonadjacent sides of the decagon, and there are 2 different pairings of this form. As shown in the figure, the requested number of pairings is $1+5+5+2=13$.
答案(C):这个问题可以用一个正十边形来建模,并画出5条对角线,把每个顶点与其对面的顶点连接起来。两个顶点之间的一条线段表示由这两个顶点代表的人彼此认识。见下图。所求的配对等价于在该图的15条线段中选出5条,使得同一组中的任意两条线段不共享端点。(这在图论中称为完美匹配。)配对的数量可以通过关注配对中使用了多少条对角线来计数。 • 使用全部5条对角线的配对有1种;并且任何包含4条对角线的配对都必须包含全部5条对角线。 • 假设某个配对恰好使用3条对角线。如果这3条对角线的端点中有3个是十边形上相邻的连续顶点,那么可以用十边形的边作为另外2条线段来形成配对。这种形式共有5种不同的配对。另一方面,任何包含3条对角线且其端点不是十边形上连续顶点的配对,都必须使用全部对角线。 • 恰好使用2条对角线的配对不存在,因为任何包含2条对角线的配对都会迫使至少使用3条对角线。 • 如果某个配对恰好使用1条对角线,那么其余部分的配对被唯一确定。这种形式共有5种不同的配对。 • 如果某个配对不使用对角线,那么它必须使用十边形中互不相邻的边,这种形式共有2种不同的配对。 如图所示,所求配对数为$1+5+5+2=13$。
solution
Topics
Related Questions
Practice full AMC exams on amcdrill.
Try full-length practice and diagnostics at www.amcdrill.com.