AMC10 2024 B
AMC10 2024 B · Q3
AMC10 2024 B · Q3. It mainly tests Linear inequalities, Word problems (algebra).
For how many integer values of $x$ is $|2x| \leq 7 \pi$
有整数 $x$ 满足 $|2x| \leq 7 \pi$ 共有多少个?
(A)
16
16
(B)
17
17
(C)
19
19
(D)
20
20
(E)
21
21
Answer
Correct choice: (E)
正确答案:(E)
Solution
$\pi = 3.14159\dots$ is slightly less than $\dfrac{22}{7} = 3.\overline{142857}$. So $7\pi \approx 21.9$
The inequality expands to be $-21.9 \le 2x \le 21.9$. We find that $x$ can take the integer values between $-10$ and $10$ inclusive. There are $\boxed{\text{E. }21}$ such values.
Note that if you did not know whether $\pi$ was greater than or less than $\dfrac{22}{7}$, then you might perform casework. In the case that $\pi > \dfrac{22}{7}$, the valid solutions are between $-11$ and $11$ inclusive: $23$ solutions. Since, $23$ is not an answer choice, we can be confident that $\pi < \dfrac{22}{7}$, and that $\boxed{\text{E. } 21}$ is the correct answer.
$\pi = 3.14159\dots$ 略小于 $\dfrac{22}{7} = 3.\overline{142857}$。所以 $7\pi \approx 21.9$
不等式展开为 $-21.9 \le 2x \le 21.9$。$x$ 可以取 $-10$ 到 $10$ 之间的整数值,共 $\boxed{\text{E. }21}$ 个。
注意,如果你不知道 $\pi$ 是否大于或小于 $\dfrac{22}{7}$,可以分类讨论。如果 $\pi > \dfrac{22}{7}$,则解为 $-11$ 到 $11$ 共23个。由于23不是选项,我们可以确信 $\pi < \dfrac{22}{7}$,正确答案为 $\boxed{\text{E. } 21}$。
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