AMC8 2023
AMC8 2023 · Q10
AMC8 2023 · Q10. It mainly tests Word problems (algebra), Fractions.
Harold made a plum pie to take on a picnic. He was able to eat only $\frac{1}{4}$ of the pie, and he left the rest for his friends. A moose came by and ate $\frac{1}{3}$ of what Harold left behind. After that, a porcupine ate $\frac{1}{3}$ of what the moose left behind. How much of the original pie still remained after the porcupine left?
Harold 做了一个李子派带去野餐。他只吃了派的三分之一,将剩下的留给了朋友。一只驼鹿过来吃了 Harold 留下的三分之一。在此之后,一只豪猪吃了驼鹿留下三分之一的三分之一。豪猪离开后,原派还剩下多少?
(A)
\ \frac{1}{12}
\ \frac{1}{12}
(B)
\ \frac{1}{6}
\ \frac{1}{6}
(C)
\ \frac{1}{4}
\ \frac{1}{4}
(D)
\ \frac{1}{3}
\ \frac{1}{3}
(E)
\ \frac{5}{12}
\ \frac{5}{12}
Answer
Correct choice: (D)
正确答案:(D)
Solution
Note that:
- Harold ate $\frac14$ of the pie. After that, $1-\frac14=\frac34$ of the pie was left behind.
- The moose ate $\frac13\cdot\frac34 = \frac14$ of the pie. After that, $\frac34 - \frac14 = \frac12$ of the pie was left behind.
- The porcupine ate $\frac13\cdot\frac12 = \frac16$ of the pie. After that, $\frac12 - \frac16 = \boxed{\textbf{(D)}\ \frac{1}{3}}$ of the pie was left behind.
More simply, we can condense the solution above into the following equation: \[\left(1-\frac14\right)\left(1-\frac13\right)\left(1-\frac13\right) = \frac34\cdot\frac23\cdot\frac23 = \frac13.\]
注意:
- Harold 吃了 $\frac14$ 的派。之后,剩下 $1-\frac14=\frac34$ 的派。
- 驼鹿吃了 $\frac13\cdot\frac34 = \frac14$ 的派。之后,剩下 $\frac34 - \frac14 = \frac12$ 的派。
- 豪猪吃了 $\frac13\cdot\frac12 = \frac16$ 的派。之后,剩下 $\frac12 - \frac16 = \boxed{\textbf{(D)}\ \frac{1}{3}}$ 的派。
更简单地,我们可以将上面的解浓缩为以下方程: \[\left(1-\frac14\right)\left(1-\frac13\right)\left(1-\frac13\right) = \frac34\cdot\frac23\cdot\frac23 = \frac13.\]
Topics
Related Questions
Practice full AMC exams on amcdrill.
Try full-length practice and diagnostics at www.amcdrill.com.