AMC8 2014

AMC8 2014 · Q2

AMC8 2014 · Q2. It mainly tests Money / coins.

Paul owes Paula $35$ cents and has a pocket full of $5$-cent coins, $10$-cent coins, and $25$-cent coins that he can use to pay her. What is the difference between the largest and the smallest number of coins he can use to pay her?

保罗欠宝拉35美分，他口袋里有5美分、10美分和25美分的硬币，可以用来还钱。用来还钱的硬币数最大值和最小值的差是多少？

(A) 1 1

(B) 2 2

(D) 4 4

(E) 5 5

Answer

Correct choice: (E)

正确答案：（E）

Solution

The fewest amount of coins that can be used is $2$ (a quarter and a dime). The greatest amount is $7$, if he only uses nickels. Therefore we have $7-2=\boxed{\textbf{(E)}~5}$.

最少用的硬币数是2枚（一枚25美分和一枚10美分）。最多用的硬币数是7枚，如果他只用5美分硬币。因此差值是 $7-2=\boxed{\textbf{(E)}~5}$。

Topics

AR.014 Money / coins