AMC12 2009 B
AMC12 2009 B · Q1
AMC12 2009 B · Q1. It mainly tests Money / coins, Divisibility & factors.
Each morning of her five-day workweek, Jane bought either a $50$-cent muffin or a $75$-cent bagel. Her total cost for the week was a whole number of dollars. How many bagels did she buy?
Jane 在她五天工作周的每个早晨,都会买一个 $50$ 美分的松饼或一个 $75$ 美分的百吉饼。她这一周的总花费是整数美元。她买了多少个百吉饼?
(A)
1
1
(B)
2
2
(C)
3
3
(D)
4
4
(E)
5
5
Answer
Correct choice: (B)
正确答案:(B)
Solution
If Jane bought one more bagel but one fewer muffin, then her total cost for the week would increase by $25$ cents.
If Jane bought $1$ bagel, then she bought $4$ muffins. Her total cost for the week would be $75\cdot1+50\cdot4=275$ cents, or $2.75$ dollars. Clearly, she bought one more bagel but one fewer muffin at a total cost of $3.00$ dollars. Therefore, she bought $\boxed{\textbf{(B) } 2}$ bagels.
如果 Jane 多买 $1$ 个百吉饼而少买 $1$ 个松饼,那么她这一周的总花费将增加 $25$ 美分。
如果 Jane 买了 $1$ 个百吉饼,那么她买了 $4$ 个松饼。她这一周的总花费为 $75\cdot1+50\cdot4=275$ 美分,即 $2.75$ 美元。显然,她再多买一个百吉饼并少买一个松饼时,总花费为 $3.00$ 美元。因此,她买了 $\boxed{\textbf{(B) } 2}$ 个百吉饼。
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