/

AMC8 2002

AMC8 2002 · Q3

AMC8 2002 · Q3. It mainly tests Averages (mean), Arithmetic sequences basics.

What is the smallest possible average of four distinct positive even integers?
四个不同的正偶整数的最小可能平均数是多少?
(A) 3 3
(B) 4 4
(C) 5 5
(D) 6 6
(E) 7 7
Answer
Correct choice: (C)
正确答案:(C)
Solution
The smallest average will occur when the numbers are as small as possible. The four smallest distinct positive even integers are 2, 4, 6, and 8 and their average is 5. Note: These numbers form an arithmetic sequence. The average of the numbers in any arithmetic sequence is the average of the first and last terms.
为了使平均数最小,数字应尽可能小。四个最小的不同正偶整数是2、4、6和8,它们的平均数是5。注意:这些数字构成一个等差数列。任何等差数列中数字的平均数等于首尾项的平均数。
Topics
Related Questions
Practice full AMC exams on amcdrill.
Try full-length practice and diagnostics at www.amcdrill.com.