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AMC8 2002

AMC8 2002 · Q12

AMC8 2002 · Q12. It mainly tests Probability (basic).

A board game spinner is divided into three regions labeled A, B and C. The probability of the arrow stopping on region A is $\frac{1}{3}$ and on region B is $\frac{1}{2}$. The probability of the arrow stopping on region C is
一个棋盘游戏转盘分为三个区域,标有A、B和C。箭头停在区域A的概率为$\frac{1}{3}$,停在区域B的概率为$\frac{1}{2}$。箭头停在区域C的概率是
stem
(A) $\frac{1}{12}$ $\frac{1}{12}$
(B) $\frac{1}{6}$ $\frac{1}{6}$
(C) $\frac{1}{5}$ $\frac{1}{5}$
(D) $\frac{1}{3}$ $\frac{1}{3}$
(E) $\frac{2}{5}$ $\frac{2}{5}$
Answer
Correct choice: (B)
正确答案:(B)
Solution
Since the sum of the three probabilities is 1, the probability of stopping on region $C$ is $1 - \frac{1}{3} - \frac{1}{2} = \frac{6}{6} - \frac{2}{6} - \frac{3}{6} = \frac{1}{6}$.
由于三个概率之和为1,停在区域$C$的概率为$1 - \frac{1}{3} - \frac{1}{2} = \frac{6}{6} - \frac{2}{6} - \frac{3}{6} = \frac{1}{6}$。
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