/

AMC8 1999

AMC8 1999 · Q9

AMC8 1999 · Q9. It mainly tests Inclusion–exclusion (basic).

Three flower beds overlap as shown. Bed A has 500 plants, bed B has 450 plants, and bed C has 350 plants. Beds A and B share 50 plants, while beds A and C share 100. The total number of plants is
三个花坛如图所示重叠。A 花坛有 500 株植物,B 花坛有 450 株,C 花坛有 350 株。A 和 B 共享 50 株植物,A 和 C 共享 100 株。总植物数是
stem
(A) 850 850
(B) 1000 1000
(C) 1150 1150
(D) 1300 1300
(E) 1450 1450
Answer
Correct choice: (C)
正确答案:(C)
Solution
Plants shared by two beds have been counted twice, so the total is $500 + 450 + 350 - 50 - 100 = \boxed{\text{(C)}\ 1150}$. Bed A has $350$ plants it doesn't share with B or C. Bed B has $400$ plants it doesn't share with A or C. And C has $250$ it doesn't share with A or B. The total is $350 + 400 + 250 + 50 + 100 = \boxed{\text{(C)}\ 1150}$ plants.
两个花坛共享的植物被计数了两次,所以总计是 $500 + 450 + 350 - 50 - 100 = \boxed{\text{(C)}\ 1150}$。 A 花坛有 $350$ 株不与 B 或 C 共享的植物。B 有 $400$ 株不与 A 或 C 共享的。C 有 $250$ 株不与 A 或 B 共享的。总计是 $350 + 400 + 250 + 50 + 100 = \boxed{\text{(C)}\ 1150}$ 株植物。
Topics
Related Questions
Practice full AMC exams on amcdrill.
Try full-length practice and diagnostics at www.amcdrill.com.