AMC8 1999

AMC8 1999 · Q3

AMC8 1999 · Q3. It mainly tests Fractions.

Which triplet of numbers has a sum NOT equal to 1?

哪个数字三元组的和不等于1？

(A) $(\frac{1}{2}, \frac{1}{3}, \frac{1}{6})$ $(\frac{1}{2}, \frac{1}{3}, \frac{1}{6})$

(B) $(2, -2, 1)$ $(2, -2, 1)$

(D) $(1.1, -2.1, 1.0)$ $(1.1, -2.1, 1.0)$

(E) $(-\frac{3}{2}, -\frac{5}{2}, 5)$ $(-\frac{3}{2}, -\frac{5}{2}, 5)$

Answer

Correct choice: (D)

正确答案：（D）

Solution

By adding each triplet, we can see that $\boxed{(D)}$ gives us $0$, not $1$, as our sum.

将每个三元组相加，我们可以看到$\boxed{(D)}$给出$0$，而不是$1$。

Topics