AMC8 1995

AMC8 1995 · Q6

AMC8 1995 · Q6. It mainly tests Arithmetic misc, Area & perimeter.

Figures I, II and III are squares. The perimeter of I is 12 and the perimeter of II is 24. The perimeter of III is

图形 I、II 和 III 是正方形。I 的周长是 12，II 的周长是 24。III 的周长是

(A) 9 9

(B) 18 18

(D) 72 72

(E) 81 81

Answer

Correct choice: (C)

正确答案：（C）

Solution

Since the perimeter of I is 12, its side is 3. Similarly, the side of II is 6. Hence the side of III is $3 + 6 = 9$. Thus the perimeter of III is $4 \times 9 = 36$.

由于 I 的周长是 12，其边长是 3。同样，II 的边长是 6。因此 III 的边长是 $3 + 6 = 9$。于是 III 的周长是 $4 \times 9 = 36$。

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