AMC8 1995

AMC8 1995 · Q19

AMC8 1995 · Q19. It mainly tests Patterns & sequences (misc).

The graph shows the distribution of the number of children in the families of the students in Ms. Jordan's English class. The median number of children in the family for this distribution is

图表显示了Jordan老师英语班学生家庭中孩子数量的分布。该分布中家庭孩子数量的中位数是

(A) 1 1

(B) 2 2

(D) 4 4

(E) 5 5

Answer

Correct choice: (D)

正确答案：（D）

Solution

Answer (D): Putting the number of children in each family in order from least to greatest yields $1, 1, 2, 3, 3, 4, 4, 5, 5, 5, 5, 5, 5.$ The median is the middle, or $7^{\text{th}}$ value, which is $4$.

答案（D）：将每个家庭的孩子数量按从小到大排列得到 $1, 1, 2, 3, 3, 4, 4, 5, 5, 5, 5, 5, 5.$ 中位数是中间的值，即第 $7^{\text{th}}$ 个值，为 $4$。

Topics

LM.002 Patterns & sequences (misc)