AMC8 1992

AMC8 1992 · Q8

AMC8 1992 · Q8. It mainly tests Fractions, Money / coins.

A store owner bought 1500 pencils at $0.10 each. If he sells them for $0.25 each, how many of them must he sell to make a profit of exactly $100.00?

一家店主以每支 0.10 美元的价格买了 1500 支铅笔。如果他以每支 0.25 美元的价格出售，要获得恰好 100.00 美元的利润，他必须卖出多少支？

(A) 400 400

(B) 667 667

(D) 1500 1500

(E) 1900 1900

Answer

Correct choice: (C)

正确答案：（C）

Solution

Answer (C): Since he bought 1500 pencils at \$0.10 each, he paid $1500\times\$0.10=\$150$. To make \$100 profit he must take in $\$150+\$100=\$250$. Therefore, selling the pencils for \$0.25 each, he must sell $\$250\div\$0.25=1000$ pencils.

答案（C）：由于他以每支 \$0.10 的价格买了 1500 支铅笔，他一共支付了 $1500\times\$0.10=\$150$。要获得 \$100 的利润，他的总收入必须达到 $\$150+\$100=\$250$。因此，如果以每支 \$0.25 的价格卖出，他必须卖出 $\$250\div\$0.25=1000$ 支铅笔。

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