/

AMC8 1990

AMC8 1990 · Q14

AMC8 1990 · Q14. It mainly tests Ratios & proportions, Probability (basic).

A bag contains only blue balls and green balls. There are 6 blue balls. If the probability of drawing a blue ball at random from this bag is $\frac{1}{4}$, then the number of green balls in the bag is
一个袋子里只有蓝球和绿球。有6个蓝球。从袋中随机抽取一个蓝球的概率是$\frac{1}{4}$,则袋子里的绿球数是
(A) 12 12
(B) 18 18
(C) 24 24
(D) 30 30
(E) 36 36
Answer
Correct choice: (B)
正确答案:(B)
Solution
Blue $\frac{1}{4}$, 6 blue, total 24 balls, green 18. Or green 3 times blue: $3\times6=18$.
蓝球占$\frac{1}{4}$,6个蓝球,总数24个球,绿球18个。或者绿球是蓝球的3倍:$3\times6=18$。
Topics
Related Questions
Practice full AMC exams on amcdrill.
Try full-length practice and diagnostics at www.amcdrill.com.