AMC12 2023 A
AMC12 2023 A · Q2
AMC12 2023 A · Q2. It mainly tests Systems of equations, Fractions.
The weight of $\frac{1}{3}$ of a large pizza together with $3 \frac{1}{2}$ cups of orange slices is the same as the weight of $\frac{3}{4}$ of a large pizza together with $\frac{1}{2}$ cup of orange slices. A cup of orange slices weighs $\frac{1}{4}$ of a pound. What is the weight, in pounds, of a large pizza?
一大块披萨的 $\frac{1}{3}$ 连同 $3 \frac{1}{2}$ 杯橙子片的总重量,等于一大块披萨的 $\frac{3}{4}$ 连同 $\frac{1}{2}$ 杯橙子片的总重量。一杯橙子片重 $\frac{1}{4}$ 磅。一大块披萨的重量是多少磅?
(A)
1\frac{4}{5}
1\frac{4}{5}
(B)
2
2
(C)
2\frac{2}{5}
2\frac{2}{5}
(D)
3
3
(E)
3\frac{3}{5}
3\frac{3}{5}
Answer
Correct choice: (A)
正确答案:(A)
Solution
Use a system of equations. Let $x$ be the weight of a pizza and $y$ be the weight of a cup of orange slices.
We have \[\frac{1}{3}x+\frac{7}{2}y=\frac{3}{4}x+\frac{1}{2}y.\]
Rearranging, we get \begin{align*} \frac{5}{12}x&=3y, \\ x&=\frac{36}{5}y. \end{align*}
Plugging in $\frac{1}{4}$ pounds for $y$ by the given gives $\frac{9}{5}=\boxed{\textbf{(A) }1\frac{4}{5}}.$
使用方程组。设 $x$ 为披萨的重量,$y$ 为一杯橙子片的重量。
我们有 \[\frac{1}{3}x+\frac{7}{2}y=\frac{3}{4}x+\frac{1}{2}y.\]
整理得 \begin{align*} \frac{5}{12}x&=3y, \\ x&=\frac{36}{5}y. \end{align*}
代入已知 $y=\frac{1}{4}$ 磅,得 $\frac{9}{5}=\boxed{\textbf{(A) }1\frac{4}{5}}.$
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