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AMC12 2022 A

AMC12 2022 A · Q1

AMC12 2022 A · Q1. It mainly tests Fractions.

What is the value of \[3+\frac{1}{3+\frac{1}{3+\frac13}}?\]
求\[3+\frac{1}{3+\frac{1}{3+\frac13}}\]的值。
(A) \ \frac{31}{10} \ \frac{31}{10}
(B) \ \frac{49}{15} \ \frac{49}{15}
(C) \ \frac{33}{10} \ \frac{33}{10}
(D) \ \frac{109}{33} \ \frac{109}{33}
(E) \ \frac{15}{4} \ \frac{15}{4}
Answer
Correct choice: (D)
正确答案:(D)
Solution
We have \begin{align*} 3+\frac{1}{3+\frac{1}{3+\frac13}} &= 3+\frac{1}{3+\frac{1}{\left(\frac{10}{3}\right)}} \\ &= 3+\frac{1}{3+\frac{3}{10}} \\ &= 3+\frac{1}{\left(\frac{33}{10}\right)} \\ &= 3+\frac{10}{33} \\ &= \boxed{\textbf{(D)}\ \frac{109}{33}}. \end{align*}
我们有 \begin{align*} 3+\frac{1}{3+\frac{1}{3+\frac13}} &= 3+\frac{1}{3+\frac{1}{\left(\frac{10}{3}\right)}} \\ &= 3+\frac{1}{3+\frac{3}{10}} \\ &= 3+\frac{1}{\left(\frac{33}{10}\right)} \\ &= 3+\frac{10}{33} \\ &= \boxed{\textbf{(D)}\ \frac{109}{33}}. \end{align*}
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