AMC12 2020 A
AMC12 2020 A · Q20
AMC12 2020 A · Q20. It mainly tests Basic counting (rules of product/sum), Transformations.
Let $T$ be the triangle in the coordinate plane with vertices $(0, 0)$, $(4, 0)$, and $(0, 3)$. Consider the following five isometries of the plane: rotations of $90^\circ$, $180^\circ$, and $270^\circ$ counterclockwise around the origin, reflection across the $x$-axis, and reflection across the $y$-axis. How many of the $125$ sequences of three of these transformations (not necessarily distinct) will return $T$ to its original position?
设$T$为坐标平面上的三角形,顶点为$(0, 0)$、$(4, 0)$、$(0, 3)$。考虑平面的以下五种等距变换:绕原点逆时针旋转$90^\circ$、$180^\circ$、$270^\circ$,关于$x$轴反射,关于$y$轴反射。在这125种由三个(不一定不同)这些变换组成的序列中,有多少种将$T$变回到原位置?
(A)
12
12
(B)
15
15
(C)
17
17
(D)
20
20
(E)
25
25
Answer
Correct choice: (A)
正确答案:(A)
Solution
Answer (A): If two rotations that are not inverses of each other are applied in order, then there is a unique third rotation that will return $T$ to its original position. There are $3\cdot2=6$ of these. If two different reflections across the coordinate axes are applied in order, then the $180^\circ$ rotation is the unique transformation that will return $T$ to its original position. There are $2$ of these. If the first two transformations are a rotation of $180^\circ$ and a reflection, in either order, then the other reflection is the unique transformation that will return $T$ to its original position. There are $4$ such sequences.
It remains to show that for all other choices of the first two transformations, none of the five choices for the third transformation will return $T$ to its original position. Two transformations that are inverses of each other already return $T$ to its original position, so applying a third transformation will move $T$ out of its original position. The other cases are a rotation of $90^\circ$ or $270^\circ$ followed by a horizontal or vertical reflection, or vice versa. In each case, a reflection would be needed to restore the correct orientation of the triangle, but neither a vertical reflection nor a horizontal reflection will return $T$ to its original position.
In all, there are $6+2+4=12$ sequences of three of the given transformations that will return $T$ to its original position.
答案(A):如果依次施加两个互不为逆的旋转变换,那么存在唯一的第三个旋转变换可以使 $T$ 回到原来的位置。这种情况共有 $3\cdot2=6$ 种。如果依次施加关于坐标轴的两种不同反射,那么 $180^\circ$ 旋转是使 $T$ 回到原位的唯一变换。这种情况共有 $2$ 种。如果前两个变换分别是 $180^\circ$ 旋转与一次反射(顺序任意),那么另一个反射就是使 $T$ 回到原位的唯一变换。这样的序列共有 $4$ 种。
还需要说明:对于前两个变换的其他所有选择,第三个变换的五种选择中没有一种能使 $T$ 回到原位。若两个变换互为逆,它们本身就已经使 $T$ 回到原位,因此再施加第三个变换会把 $T$ 从原位移开。其余情况是先做 $90^\circ$ 或 $270^\circ$ 的旋转再做水平或竖直反射,或顺序相反。在每种情况下,都需要一次反射来恢复三角形的正确朝向,但无论竖直反射还是水平反射都不能使 $T$ 回到原来的位置。
总之,共有 $6+2+4=12$ 个由给定变换中选取三个组成的序列,能使 $T$ 回到原来的位置。
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