AMC12 2019 B
AMC12 2019 B · Q9
AMC12 2019 B · Q9. It mainly tests Logarithms (rare), Triangles (properties).
For how many integral values of $x$ can a triangle of positive area be formed having side lengths $\log_2 x$, $\log_4 x$, and 3?
对于多少个整数值 $x$,可以形成一个正面积的三角形,其边长为 $\log_2 x$、$\log_4 x$ 和 3?
(A)
57
57
(B)
59
59
(C)
61
61
(D)
62
62
(E)
63
63
Answer
Correct choice: (B)
正确答案:(B)
Solution
Answer (B): A triangle of positive area can be formed if and only if all three Triangle Inequalities are satisfied:
$\log_2 x + \log_4 x > 3,$
$3 + \log_4 x > \log_2 x,$ and
$3 + \log_2 x > \log_4 x.$
By the Change of Base Formula,
$\log_4 x=\dfrac{\log_2 x}{\log_2 4}=\dfrac{1}{2}\log_2 x.$
Therefore the inequalities are equivalent, respectively, to
$\log_2 x>2,$
$6>\log_2 x,$ and
$\log_2 x>-6.$
These are in turn equivalent to $x>4$, $x<64$, and $x>\dfrac{1}{64}$. Because $x$ must be an integer, it must lie between $5$ and $63$, inclusive, and there are $63-4=59$ such numbers.
答案(B):当且仅当满足三条三角形不等式时,才能构成面积为正的三角形:
$\log_2 x + \log_4 x > 3,$
$3 + \log_4 x > \log_2 x,$ 且
$3 + \log_2 x > \log_4 x.$
由换底公式,
$\log_4 x=\dfrac{\log_2 x}{\log_2 4}=\dfrac{1}{2}\log_2 x.$
因此,上述不等式分别等价于
$\log_2 x>2,$
$6>\log_2 x,$ 且
$\log_2 x>-6.$
进一步分别等价于 $x>4$、$x<64$、$x>\dfrac{1}{64}$。由于 $x$ 必须是整数,所以 $x$ 必须在 $5$ 到 $63$(含)之间,共有 $63-4=59$ 个这样的整数。
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