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AMC12 2015 A

AMC12 2015 A · Q1

AMC12 2015 A · Q1. It mainly tests Exponents & radicals, Fractions.

What is the value of $(2^0 - 1 + 5^2 + 0)^{-1} \times 5$?
$(2^0 - 1 + 5^2 + 0)^{-1} \times 5$ 的值为多少？
(A) -125 -125
(B) -120 -120
(C) \frac{1}{5} \frac{1}{5}
(D) \frac{5}{24} \frac{5}{24}
(E) 25 25
Answer
Correct choice: (C)
正确答案：（C）
Solution
$(1 - 1 + 25 + 0)^{-1} \times 5 = \frac{1}{25} \times 5 = \frac{1}{5}$
$(1 - 1 + 25 + 0)^{-1} \times 5 = \frac{1}{25} \times 5 = \frac{1}{5}$
Topics
AL.008 Exponents & radicals AR.001 Fractions
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