AMC12 2014 A
AMC12 2014 A · Q1
AMC12 2014 A · Q1. It mainly tests Fractions.
What is $10\cdot\left(\tfrac{1}{2}+\tfrac{1}{5}+\tfrac{1}{10}\right)^{-1}?$
$10\cdot\left(\tfrac{1}{2}+\tfrac{1}{5}+\tfrac{1}{10}\right)^{-1}$ 等于多少?
(A)
3
3
(B)
8
8
(C)
\ \frac{25}{2}
\ \frac{25}{2}
(D)
\ \frac{170}{3}
\ \frac{170}{3}
(E)
170
170
Answer
Correct choice: (C)
正确答案:(C)
Solution
We have \[10\cdot\left(\frac{1}{2}+\frac{1}{5}+\frac{1}{10}\right)^{-1}\]
Making the denominators equal gives
\[\implies 10\cdot\left(\frac{5}{10}+\frac{2}{10}+\frac{1}{10}\right)^{-1}\]
\[\implies 10\cdot\left(\frac{5+2+1}{10}\right)^{-1}\]
\[\implies 10\cdot\left(\frac{8}{10}\right)^{-1}\]
\[\implies 10\cdot\left(\frac{4}{5}\right)^{-1}\]
\[\implies 10\cdot\frac{5}{4}\]
\[\implies \frac{50}{4}\]
Finally, simplifying gives
\[\implies \boxed{\textbf{(C)}\ \frac{25}{2}}\]
我们有 \[10\cdot\left(\frac{1}{2}+\frac{1}{5}+\frac{1}{10}\right)^{-1}\]
分母相同化得 \[\implies 10\cdot\left(\frac{5}{10}+\frac{2}{10}+\frac{1}{10}\right)^{-1}\]
\[\implies 10\cdot\left(\frac{5+2+1}{10}\right)^{-1}\]
\[\implies 10\cdot\left(\frac{8}{10}\right)^{-1}\]
\[\implies 10\cdot\left(\frac{4}{5}\right)^{-1}\]
\[\implies 10\cdot\frac{5}{4}\]
\[\implies \frac{50}{4}\]
最终化简得 \[\implies \boxed{\textbf{(C)}\ \frac{25}{2}}\]
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