AMC12 2013 B

AMC12 2013 B · Q1

AMC12 2013 B · Q1. It mainly tests Fractions, Averages (mean).

On a particular January day, the high temperature in Lincoln, Nebraska, was 16 degrees higher than the low temperature, and the average of the high and low temperatures was $3^{\circ}$. In degrees, what was the low temperature in Lincoln that day?

在某个特定的1月一天，林肯（内布拉斯加州）最高气温比最低气温高16度，而最高和最低气温的平均值为$3^{\circ}$。那天林肯的最低气温是多少度？

(A) -13 -13

(B) -8 -8

(D) -3 -3

(E) 11 11

Answer

Correct choice: (C)

正确答案：（C）

Solution

The difference between the high and low temperatures was 16 degrees, so the difference between each of these and the average temperature was 8 degrees. The low temperature was 8 degrees less than the average, so it was $3^{\circ}-8^{\circ}=-5^{\circ}$.

最高和最低气温的差是16度，因此它们与平均气温的差各为8度。最低气温比平均气温低8度，因此是$3^{\circ}-8^{\circ}=-5^{\circ}$。

Topics