AMC12 2010 A
AMC12 2010 A · Q1
AMC12 2010 A · Q1. It mainly tests Manipulating equations, Fractions.
What is $\left(20-\left(2010-201\right)\right)+\left(2010-\left(201-20\right)\right)$?
$\left(20-\left(2010-201\right)\right)+\left(2010-\left(201-20\right)\right)$ 的值是多少?
(A)
-4020
-4020
(B)
0
0
(C)
40
40
(D)
401
401
(E)
4020
4020
Answer
Correct choice: (C)
正确答案:(C)
Solution
$20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}$.
$20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}$.
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