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AMC12 2009 A

AMC12 2009 A · Q2

AMC12 2009 A · Q2. It mainly tests Fractions.

Which of the following is equal to $1 + \frac {1}{1 + \frac {1}{1 + 1}}$?
下列哪个等于 $1 + \frac {1}{1 + \frac {1}{1 + 1}}$?
(A) $\frac{5}{4}$ $\frac{5}{4}$
(B) $\frac{3}{2}$ $\frac{3}{2}$
(C) $\frac{5}{3}$ $\frac{5}{3}$
(D) 2 2
(E) 3 3
Answer
Correct choice: (C)
正确答案:(C)
Solution
We compute: \begin{align*} 1 + \frac {1}{1 + \frac {1}{1 + 1}} &= 1 + \frac {1}{1 + \frac {1}{1 + 1}} \\ &= 1 + \frac {1}{1 + \frac 12} \\ &= 1 + \frac {1}{\frac 32} \\ &= 1 + \frac 23 \\ &= \frac 53 \end{align*} This is choice $\boxed{\text{C}}$. Interesting sidenote: The continued fraction $1 + \frac {1}{1 + \frac {1}{1 + 1....}}$ is equal to the golden ratio, or $\frac{1+\sqrt{5}}{2}$.
我们计算: \begin{align*} 1 + \frac {1}{1 + \frac {1}{1 + 1}} &= 1 + \frac {1}{1 + \frac {1}{1 + 1}} \\ &= 1 + \frac {1}{1 + \frac 12} \\ &= 1 + \frac {1}{\frac 32} \\ &= 1 + \frac 23 \\ &= \frac 53 \end{align*} 因此对应选项为 $\boxed{\text{C}}$。 有趣的补充:连分数 $1 + \frac {1}{1 + \frac {1}{1 + 1....}}$ 等于黄金比例,即 $\frac{1+\sqrt{5}}{2}$。
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