AMC10 2020 A

AMC10 2020 A · Q1

AMC10 2020 A · Q1. It mainly tests Linear equations, Fractions.

What value of $x$ satisfies $x - \frac{3}{4} = \frac{5}{12} - \frac{1}{3}$?

什么值$x$满足方程$x - \frac{3}{4} = \frac{5}{12} - \frac{1}{3}$？

(A) $-\frac{2}{3}$ $-\frac{2}{3}$

(B) $\frac{7}{36}$ $\frac{7}{36}$

(D) $\frac{2}{3}$ $\frac{2}{3}$

(E) $\frac{5}{6}$ $\frac{5}{6}$

Answer

Correct choice: (E)

正确答案：（E）

Solution

Adding $\frac{3}{4}$ to both sides of the equation gives $x = \frac{5}{12} - \frac{1}{3} + \frac{3}{4} = \frac{5}{12} - \frac{4}{12} + \frac{9}{12} = \frac{10}{12} = \frac{5}{6}$.

在方程两边加$\frac{3}{4}$，得到$x = \frac{5}{12} - \frac{1}{3} + \frac{3}{4} = \frac{5}{12} - \frac{4}{12} + \frac{9}{12} = \frac{10}{12} = \frac{5}{6}$。

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