AMC10 2010 B
AMC10 2010 B · Q6
AMC10 2010 B · Q6. It mainly tests Triangles (properties), Circle theorems.
A circle is centered at $O$, $AB$ is a diameter and $C$ is a point on the circle with $\angle COB=50^\circ$. What is the degree measure of $\angle CAB$?
一个圆以 $O$ 为圆心,$AB$ 是直径,$C$ 是圆上一点,且 $\angle COB=50^\circ$。$\angle CAB$ 的度数是多少?
(A)
20
20
(B)
25
25
(C)
45
45
(D)
50
50
(E)
65
65
Answer
Correct choice: (B)
正确答案:(B)
Solution
Note that $\angle AOC=180^\circ-50^\circ=130^\circ$. Because $\triangle AOC$ is isosceles, $\angle CAB=\frac{1}{2}(180^\circ-130^\circ)=25^\circ$.
注意到 $\angle AOC=180^\circ-50^\circ=130^\circ$。因为 $\triangle AOC$ 是等腰三角形,$\angle CAB=\frac{1}{2}(180^\circ-130^\circ)=25^\circ$。
Topics
Related Questions
Practice full AMC exams on amcdrill.
Try full-length practice and diagnostics at www.amcdrill.com.