AMC10 2010 A

AMC10 2010 A · Q4

AMC10 2010 A · Q4. It mainly tests Fractions, Inequalities with integers (floor/ceiling basics).

A book that is to be recorded onto compact discs takes 412 minutes to read aloud. Each disc can hold up to 56 minutes of reading. Assume that the smallest possible number of discs is used and that each disc contains the same length of reading. How many minutes of reading will each disc contain?

一本将要录制到光盘上的书朗读需要 412 分钟。每张光盘最多可容纳 56 分钟的朗读。假设使用最少的光盘数，且每张光盘包含相同长度的朗读。每张光盘将包含多少分钟的朗读？

(A) 50.2 50.2

(B) 51.5 51.5

(D) 53.8 53.8

(E) 55.2 55.2

Answer

Correct choice: (B)

正确答案：（B）

Solution

Answer (B): Because $412 \div 56$ is between 7 and 8, the reading will need 8 discs. Therefore each disc will contain $412 \div 8 = 51.5$ minutes of reading.

答案（B）：因为 $412 \div 56$ 介于 7 和 8 之间，所以这段朗读需要 8 张光盘。因此每张光盘将包含 $412 \div 8 = 51.5$ 分钟的朗读内容。

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