AMC10 2005 A
AMC10 2005 A · Q9
AMC10 2005 A · Q9. It mainly tests Probability (basic).
Three tiles are marked X and two other tiles are marked O. The five tiles are randomly arranged in a row. What is the probability that the arrangement reads XOXOX?
有 3 块标有 X 的瓦片和 2 块标有 O 的瓦片。5 块瓦片随机排成一排。排列为 XOXOX 的概率是多少?
(A)
$\frac{1}{12}$
$\frac{1}{12}$
(B)
$\frac{1}{10}$
$\frac{1}{10}$
(C)
$\frac{1}{6}$
$\frac{1}{6}$
(D)
$\frac{1}{4}$
$\frac{1}{4}$
(E)
$\frac{1}{3}$
$\frac{1}{3}$
Answer
Correct choice: (B)
正确答案:(B)
Solution
There are three X's and two O's, and the tiles are selected without replacement, so the probability is $\frac{3}{5} \cdot \frac{2}{4} \cdot \frac{2}{3} \cdot \frac{1}{2} \cdot \frac{1}{1} = \frac{1}{10}$.
有三个 X 和两个 O,瓦片无放回选择,所以概率是 $\frac{3}{5} \cdot \frac{2}{4} \cdot \frac{2}{3} \cdot \frac{1}{2} \cdot \frac{1}{1} = \frac{1}{10}$。
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