AMC10 2002 A
AMC10 2002 A · Q2
AMC10 2002 A · Q2. It mainly tests Fractions.
For the nonzero numbers $a$, $b$, and $c$, define $(a, b, c) = \frac{a}{b} + \frac{b}{c} + \frac{c}{a}$. Find $(2, 12, 9)$.
对于非零数 $a$、$b$ 和 $c$,定义 $(a, b, c) = \frac{a}{b} + \frac{b}{c} + \frac{c}{a}$。求 $(2, 12, 9)$ 的值。
(A)
4
4
(B)
5
5
(C)
6
6
(D)
7
7
(E)
8
8
Answer
Correct choice: (C)
正确答案:(C)
Solution
(C) We have
\[(2,12,9)=\frac{2}{12}+\frac{12}{9}+\frac{9}{2}=\frac{1}{6}+\frac{4}{3}+\frac{9}{2}=\frac{1+8+27}{6}=\frac{36}{6}=6.\]
(C)我们有
\[(2,12,9)=\frac{2}{12}+\frac{12}{9}+\frac{9}{2}=\frac{1}{6}+\frac{4}{3}+\frac{9}{2}=\frac{1+8+27}{6}=\frac{36}{6}=6.\]
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