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AMC10 2002 A

AMC10 2002 A · Q2

AMC10 2002 A · Q2. It mainly tests Fractions.

For the nonzero numbers $a$, $b$, and $c$, define $(a, b, c) = \frac{a}{b} + \frac{b}{c} + \frac{c}{a}$. Find $(2, 12, 9)$.
对于非零数 $a$、$b$ 和 $c$,定义 $(a, b, c) = \frac{a}{b} + \frac{b}{c} + \frac{c}{a}$。求 $(2, 12, 9)$ 的值。
(A) 4 4
(B) 5 5
(C) 6 6
(D) 7 7
(E) 8 8
Answer
Correct choice: (C)
正确答案:(C)
Solution
(C) We have \[(2,12,9)=\frac{2}{12}+\frac{12}{9}+\frac{9}{2}=\frac{1}{6}+\frac{4}{3}+\frac{9}{2}=\frac{1+8+27}{6}=\frac{36}{6}=6.\]
(C)我们有 \[(2,12,9)=\frac{2}{12}+\frac{12}{9}+\frac{9}{2}=\frac{1}{6}+\frac{4}{3}+\frac{9}{2}=\frac{1+8+27}{6}=\frac{36}{6}=6.\]
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