Suppose that $13$ cards numbered $1, 2, 3, \ldots, 13$ are arranged in a row. The task is to pick them up in numerically increasing order, working repeatedly from left to right. In the example below, cards $1, 2, 3$ are picked up on the first pass, $4$ and $5$ on the second pass, $6$ on the third pass, $7, 8, 9, 10$ on the fourth pass, and $11, 12, 13$ on the fifth pass. For how many of the $13!$ possible orderings of the cards will the $13$ cards be picked up in exactly two passes?
假设 13 张编号为 $1, 2, 3, \ldots, 13$ 的卡片排成一排。任务是从左到右反复拾取它们,按数字递增顺序拾取。在下面的例子中,第一遍拾取卡片 $1, 2, 3$,第二遍拾取 $4$ 和 $5$,第三遍拾取 $6$,第四遍拾取 $7, 8, 9, 10$,第五遍拾取 $11, 12, 13$。在 13! 种可能的卡片排列中,有多少种会使得 13 张卡片恰好在两遍中被拾取完?