As shown in the figure, line segment $\overline{AD}$ is trisected by points $B$ and $C$ so that $AB = BC = CD = 2$. Three semicircles of radius 1, $\overline{AEB}$, $\overline{BFC}$, and $\overline{CGD}$, have their diameters on $\overline{AD}$, lie in the same halfplane determined by line $AD$, and are tangent to line $EG$ at $E$, $F$, and $G$, respectively. A circle of radius 2 has its center at $F$. The area of the region inside the circle but outside the three semicircles, shaded in the figure, can be expressed in the form $\frac{a}{b} \cdot \pi - \sqrt{c} + d$, where $a, b, c,$ and $d$ are positive integers and $a$ and $b$ are relatively prime. What is $a + b + c + d$?
如图所示,线段 $\overline{AD}$ 被点 $B$ 和 $C$ 三等分,使得 $AB = BC = CD = 2$。三个半径为1的半圆 $\overline{AEB}$、$\overline{BFC}$ 和 $\overline{CGD}$,直径在 $\overline{AD}$ 上,位于线 $AD$ 确定同一半平面,且分别在 $E$、$F$、$G$ 处与线 $EG$ 相切。半径为2的圆以 $F$ 为中心。圆内但三个半圆外的阴影区域面积可表示为 $\frac{a}{b} \cdot \pi - \sqrt{c} + d$,其中 $a, b, c,$ 和 $d$ 为正整数且 $a$ 与 $b$ 互素。求 $a + b + c + d$?