Let $T_1$ be a triangle with side lengths $2011$, $2012$, and $2013$. For $n \geq 1$, if $T_n = \triangle ABC$ and $D, E$, and $F$ are the points of tangency of the incircle of $\triangle ABC$ to the sides $AB$, $BC$, and $AC$, respectively, then $T_{n+1}$ is a triangle with side lengths $AD, BE$, and $CF$, if it exists. What is the perimeter of the last triangle in the sequence $\left(T_n\right)$?
设 $T_1$ 是一个边长为 $2011$, $2012$, $2013$ 的三角形。对 $n \geq 1$,若 $T_n = \triangle ABC$,且 $D, E, F$ 分别是 $\triangle ABC$ 的内切圆与边 $AB$, $BC$, $AC$ 的切点,则(若存在)$T_{n+1}$ 是一边长为 $AD, BE, CF$ 的三角形。序列 $\left(T_n\right)$ 中最后一个三角形的周长是多少?