Let $T_1$ be a triangle with sides $2011$, $2012$, and $2013$. For $n \ge 1$, if $T_n=\triangle ABC$ and $D$, $E$, and $F$ are the points of tangency of the incircle of $\triangle ABC$ to the sides $AB$, $BC$, and $AC$, respectively, then $T_{n+1}$ is a triangle with side lengths $AD$, $BE$, and $CF$, if it exists. What is the perimeter of the last triangle in the sequence $(T_n)$?
设 $T_1$ 为一边长分别为 $2011$、$2012$、$2013$ 的三角形。对任意 $n \ge 1$,若 $T_n=\triangle ABC$,且 $D,E,F$ 分别为 $\triangle ABC$ 的内切圆与边 $AB,BC,AC$ 的切点,则(若存在)$T_{n+1}$ 定义为一三角形,其三边长分别为 $AD,BE,CF$。求序列 $(T_n)$ 中最后一个三角形的周长。