AMC8 2017

AMC8 2017 · Q13

AMC8 2017 · Q13. It mainly tests Logic puzzles.

Peter, Emma, and Kyler played chess with each other. Peter won 4 games and lost 2 games. Emma won 3 games and lost 3 games. If Kyler lost 3 games, how many games did he win?

Peter、Emma和Kyler互相下棋对弈。Peter赢了4局，输了2局。Emma赢了3局，输了3局。如果Kyler输了3局，他赢了多少局？

(A) 0 0

(B) 1 1

(D) 3 3

(E) 4 4

Answer

Correct choice: (B)

正确答案：（B）

Solution

Answer (B): Whenever a person wins a game, another person loses that game. So the total number of wins equals the total number of losses. Peter, Emma, and Kyler lost $2+3+3=8$ games altogether, and Peter and Emma won $4+3=7$ games in total. Therefore, Kyler won $1$ game.

答案 (B)：每当一人赢一局，就有另一人输一局。因此，总胜场数等于总败场数。Peter、Emma 和 Kyler 一共输了 $2+3+3=8$ 局，而 Peter 和 Emma 一共赢了 $4+3=7$ 局。因此，Kyler 赢了 $1$ 局。

Topics

LM.001 Logic puzzles