AMC8 2014
AMC8 2014 · Q25
AMC8 2014 · Q25. It mainly tests Rates (speed), Circle theorems.
A straight one-mile stretch of highway, 40 feet wide, is closed. Robert rides his bike on a path composed of semicircles as shown. If he rides at 5 miles per hour, how many hours will it take to cover the one-mile stretch?
Note: 1 mile = 5280 feet
一条直直的一英里长、高度为40英尺的公路被封闭。罗伯特骑自行车沿着如图所示由半圆组成的路径前进。如果他的骑行速度为每小时5英里,他需要多少小时才能骑完这一英里路程?
注:1 英里 = 5280 英尺
(A)
\frac{\pi}{11}
\frac{\pi}{11}
(B)
\frac{\pi}{10}
\frac{\pi}{10}
(C)
\frac{\pi}{5}
\frac{\pi}{5}
(D)
\frac{2\pi}{5}
\frac{2\pi}{5}
(E)
\frac{2\pi}{3}
\frac{2\pi}{3}
Answer
Correct choice: (B)
正确答案:(B)
Solution
There are two possible interpretations of the problem: that the road as a whole is $40$ feet wide, or that each lane is $40$ feet wide. Both interpretations will arrive at the same result. However, let us stick with the first interpretation for simplicity. Each lane must then be $20$ feet wide, so Robert must be riding his bike in semicircles with radius $20$ feet and diameter $40$ feet. Since the road is $5280$ feet long, over the whole mile, Robert rides $\frac{5280}{40} =132$ semicircles in total. Were the semicircles full circles, their circumference would be $2\pi\cdot 20=40\pi$ feet; as it is, the circumference of each is half that, or $20\pi$ feet. Therefore, over the stretch of highway, Robert rides a total of $132\cdot 20\pi =2640\pi$ feet, which is equivalent to $\frac{\pi}{2}$ miles. Robert rides at 5 miles per hour, so divide the $\frac{\pi}{2}$ miles by $5$ mph (because $t = \frac{d}{r}$ and time = distance/rate) to arrive at $\boxed{\textbf{(B) }\frac{\pi}{10}}$ hours.
Edit: If you are confused about the lanes, watch the video below :)
这个问题有两种可能的理解:要么整个道路宽度为 $40$ 英尺,要么每条车道宽度为 $40$ 英尺。两种理解方式最终都会得出相同的结果。但为了简单起见,我们采用第一种理解。这样每条车道宽度为 $20$ 英尺,因此罗伯特必须骑行半径为 $20$ 英尺、直径为 $40$ 英尺的半圆。由于道路全长为 $5280$ 英尺,整个一英里内,罗伯特总共骑行了 $\frac{5280}{40} =132$ 个半圆。如果这些半圆是完整的圆圈,它们的周长应为 $2\pi \cdot 20=40\pi$ 英尺;而实际每个半圆周长是其一半,即 $20\pi$ 英尺。因此,在这段公路上,罗伯特共骑行了 $132 \cdot 20\pi =2640\pi$ 英尺,相当于 $\frac{\pi}{2}$ 英里。罗伯特骑行速度为每小时5英里,所以时间为距离除以速度,即将 $\frac{\pi}{2}$ 英里除以 $5$ 英里/小时,得出时间为 $\boxed{\textbf{(B) }\frac{\pi}{10}}$ 小时。
编辑:如果你对车道宽度有疑问,可以观看下面的视频 :)
Topics
Related Questions
Practice full AMC exams on amcdrill.
Try full-length practice and diagnostics at www.amcdrill.com.