AMC8 1999
AMC8 1999 · Q6
AMC8 1999 · Q6. It mainly tests Logic puzzles.
Bo, Coe, Flo, Jo, and Moe have different amounts of money. Neither Jo nor Bo has as much money as Flo. Both Bo and Coe have more than Moe. Jo has more than Moe, but less than Bo. Who has the least amount of money?
Bo、Coe、Flo、Jo 和 Moe 有不同数量的钱。Jo 和 Bo 都没有 Flo 多钱。Bo 和 Coe 都比 Moe 多钱。Jo 比 Moe 多,但比 Bo 少。谁的钱最少?
(A)
Bo
Bo
(B)
Coe
Coe
(C)
Flo
Flo
(D)
Jo
Jo
(E)
Moe
Moe
Answer
Correct choice: (E)
正确答案:(E)
Solution
Use logic to solve this problem. You don't actually need to use any equations.
Neither Jo nor Bo has as much money as Flo. So Flo clearly does not have the least amount of money. Rule out Flo.
Both Bo and Coe have more than Moe. Rule out Bo and Coe; they clearly do not have the least amount of money.
Jo has more than Moe. Rule out Jo.
The only person who has not been ruled out is Moe. So $\boxed{\text{(E)}}$ is the answer.
使用逻辑解决这个问题。你实际上不需要使用任何方程。
Jo 和 Bo 都没有 Flo 多钱。所以 Flo 显然不是最少的。排除 Flo。
Bo 和 Coe 都比 Moe 多。排除 Bo 和 Coe;他们显然不是最少的。
Jo 比 Moe 多。排除 Jo。
唯一没有被排除的人是 Moe。所以 \boxed{\text{(E)}} 是答案。
Topics
Related Questions
Practice full AMC exams on amcdrill.
Try full-length practice and diagnostics at www.amcdrill.com.