AMC8 1999

AMC8 1999 · Q12

AMC8 1999 · Q12. It mainly tests Percent, Ratios & proportions.

The ratio of the number of games won to the number of games lost (no ties) by the Middle School Middies is 11/4. To the nearest whole percent, what percent of its games did the team lose?

中学生Middies队的胜场数与负场数（无平局）的比为11/4。该队负场的百分比（四舍五入到最接近的整百分比）是多少？

(A) 24 24

(B) 27 27

(D) 45 45

(E) 73 73

Answer

Correct choice: (B)

正确答案：（B）

Solution

The ratio means that for every $11$ games won, $4$ are lost, so the team has won $11x$ games, lost $4x$ games, and played $15x$ games for some positive integer $x$. The percentage of games lost is just $\dfrac{4x}{15x}\times100=\dfrac{4}{15}\times 100=26.\overline{6}\%\approx\boxed{\text{(B)}\ 27\%}$

该比意味着每赢$11$场，输$4$场，因此赢$11x$场，输$4x$场，共打$15x$场（$x$为正整数）。负场百分比为$\dfrac{4x}{15x}\times100=\dfrac{4}{15}\times 100=26.\overline{6}\%\approx\boxed{\text{(B)}\ 27\%}$

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