AMC8 1996
AMC8 1996 · Q12
AMC8 1996 · Q12. It mainly tests Averages (mean), Arithmetic misc.
The number should be removed from the list 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 so that the average of the remaining numbers is 6.1?
从列表 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 中移除哪个数，使得剩余数字的平均数为 6.1？
(A)
4
4
(B)
5
5
(C)
6
6
(D)
7
7
(E)
8
8
Answer
Correct choice: (B)
正确答案：（B）
Solution
Answer (B): The sum of the eleven numbers is 66. For the average of ten numbers to be 6.1, the sum of the ten numbers must be $10 \times 6.1 = 61$. Thus, remove the 5.
答案（B）：这 11 个数的和是 66。要使 10 个数的平均数为 6.1，这 10 个数的和必须是 $10 \times 6.1 = 61$。因此，去掉 5。
Topics
Related Questions
Practice full AMC exams on amcdrill.
Try full-length practice and diagnostics at www.amcdrill.com.