AMC8 1995

AMC8 1995 · Q16

AMC8 1995 · Q16. It mainly tests Rates (speed), Arithmetic misc.

Students from three middle schools worked on a summer project. Seven students from Allen School worked for 3 days. Four students from Balboa School worked for 5 days. Five students from Carver School worked for 9 days. The total amount paid for the students' work was \$774. Assuming each student received the same amount for a day's work, how much did the students from Balboa School earn altogether?

来自三所中学的学生参加了一个暑期项目。Allen学校的7名学生工作了3天。Balboa学校的4名学生工作了5天。Carver学校的5名学生工作了9天。学生工作的总报酬为774美元。假设每位学生每天的报酬相同，Balboa学校的学生总共赚了多少钱？

(A) $9.00 $9.00

(B) $48.38 $48.38

(D) $193.50 $193.50

(E) $258.00 $258.00

Answer

Correct choice: (C)

正确答案：（C）

Solution

Answer (C): Tabulate the data: \[ \begin{array}{lcl} \text{Allen School: } 7 \text{ students for } 3 \text{ days} & = & 21 \text{ worker days} \\ \text{Balboa School: } 4 \text{ students for } 5 \text{ days} & = & 20 \text{ worker days} \\ \text{Carver School: } 5 \text{ students for } 9 \text{ days} & = & 45 \text{ worker days} \\ \hline \textbf{Total:} & & 86 \text{ worker days} \end{array} \] Hence, $774 \div 86 = 9$ per worker day. Thus the students from Balboa School earned \$9 per worker day, for a total of \$180.

答案（C）：将数据列表如下： \[ \begin{array}{lcl} \text{Allen 学校：} 7 \text{ 名学生工作 } 3 \text{ 天} & = & 21 \text{ 个工日} \\ \text{Balboa 学校：} 4 \text{ 名学生工作 } 5 \text{ 天} & = & 20 \text{ 个工日} \\ \text{Carver 学校：} 5 \text{ 名学生工作 } 9 \text{ 天} & = & 45 \text{ 个工日} \\ \hline \textbf{合计：} & & 86 \text{ 个工日} \end{array} \] 因此，$774 \div 86 = 9$（每个工日）。所以 Balboa 学校的学生每个工日赚 \$9，总计 \$180。

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