AMC8 1995
AMC8 1995 · Q14
AMC8 1995 · Q14. It mainly tests Linear equations, Percent.
A team won 40 of its first 50 games. How many of the remaining 40 games must this team win so it will won exactly 70% of its games for the season?
一支队伍在前50场比赛中赢了40场。要使该队整个赛季的胜率恰好为70%,它还需在剩余40场比赛中赢多少场?
(A)
20
20
(B)
23
23
(C)
28
28
(D)
30
30
(E)
35
35
Answer
Correct choice: (B)
正确答案:(B)
Solution
The total number of games for the season is 50+40 = 90 games. Since 70% of 90 games is 63, it follows that 63 − 40 = 23 more wins are needed.
赛季总比赛数为50+40 = 90场。90场的70%是63,因此还需要63 − 40 = 23场胜利。
Topics
Related Questions
Practice full AMC exams on amcdrill.
Try full-length practice and diagnostics at www.amcdrill.com.