AMC8 1995

AMC8 1995 · Q11

AMC8 1995 · Q11. It mainly tests Rates (speed), Ratios in geometry.

Jane can walk any distance in half the time it takes Hector to walk the same distance. They set off in opposite directions around the outside of the 18-block area as shown. When they meet for the first time, they will be closest to

简可以以海克托走相同距离一半的时间走任何距离。他们朝着相反方向绕着图示的18街区区域外围出发。当他们第一次相遇时，他们将最接近于

(A) A A

(B) B B

(D) D D

(E) E E

Answer

Correct choice: (D)

正确答案：（D）

Solution

Jane covers twice as much distance as Hector in the same time. When they meet, they will have covered 18 blocks together. Since 12+6 = 18 and 12 is twice 6, they must meet 6 blocks counterclockwise from the start, which is point D.

简在相同时间内走的距离是海克托的两倍。当他们相遇时，他们总共走了18街区。因为12+6=18且12是6的两倍，他们一定在从起点逆时针6街区处相遇，即点D。

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