AMC12 2010 B
AMC12 2010 B · Q5
AMC12 2010 B · Q5. It mainly tests Manipulating equations.
Lucky Larry's teacher asked him to substitute numbers for $a$, $b$, $c$, $d$, and $e$ in the expression $a-(b-(c-(d+e)))$ and evaluate the result. Larry ignored the parenthese but added and subtracted correctly and obtained the correct result by coincidence. The number Larry substituted for $a$, $b$, $c$, and $d$ were $1$, $2$, $3$, and $4$, respectively. What number did Larry substitute for $e$?
Lucky Larry 的老师让他在表达式 $a-(b-(c-(d+e)))$ 中用数字替换 $a$、$b$、$c$、$d$ 和 $e$ 并计算结果。Larry 忽略了括号但正确地进行了加减法,并碰巧得到了正确结果。Larry 分别用 $1$、$2$、$3$ 和 $4$ 替换了 $a$、$b$、$c$ 和 $d$。Larry 用什么数字替换了 $e$?
(A)
-5
-5
(B)
-3
-3
(C)
0
0
(D)
3
3
(E)
5
5
Answer
Correct choice: (D)
正确答案:(D)
Solution
We simply plug in the numbers
\[1 - 2 - 3 - 4 + e = 1 - (2 - (3 - (4 + e)))\]
\[-8 + e = -2 - e\]
\[2e = 6\]
\[e = 3 \;\;(D)\]
直接代入:
\[1 - 2 - 3 - 4 + e = 1 - (2 - (3 - (4 + e)))\]
\[-8 + e = -2 - e\]
\[2e = 6\]
\[e = 3 \;\;(D)\]
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