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AMC12 2010 B

AMC12 2010 B · Q5

AMC12 2010 B · Q5. It mainly tests Manipulating equations.

Lucky Larry's teacher asked him to substitute numbers for $a$, $b$, $c$, $d$, and $e$ in the expression $a-(b-(c-(d+e)))$ and evaluate the result. Larry ignored the parenthese but added and subtracted correctly and obtained the correct result by coincidence. The number Larry substituted for $a$, $b$, $c$, and $d$ were $1$, $2$, $3$, and $4$, respectively. What number did Larry substitute for $e$?
Lucky Larry 的老师让他在表达式 $a-(b-(c-(d+e)))$ 中用数字替换 $a$、$b$、$c$、$d$ 和 $e$ 并计算结果。Larry 忽略了括号但正确地进行了加减法,并碰巧得到了正确结果。Larry 分别用 $1$、$2$、$3$ 和 $4$ 替换了 $a$、$b$、$c$ 和 $d$。Larry 用什么数字替换了 $e$?
(A) -5 -5
(B) -3 -3
(C) 0 0
(D) 3 3
(E) 5 5
Answer
Correct choice: (D)
正确答案:(D)
Solution
We simply plug in the numbers \[1 - 2 - 3 - 4 + e = 1 - (2 - (3 - (4 + e)))\] \[-8 + e = -2 - e\] \[2e = 6\] \[e = 3 \;\;(D)\]
直接代入: \[1 - 2 - 3 - 4 + e = 1 - (2 - (3 - (4 + e)))\] \[-8 + e = -2 - e\] \[2e = 6\] \[e = 3 \;\;(D)\]
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