AMC12 2009 A
AMC12 2009 A · Q6
AMC12 2009 A · Q6. It mainly tests Exponents & radicals, Primes & prime factorization.
Suppose that $P = 2^m$ and $Q = 3^n$. Which of the following is equal to $12^{mn}$ for every pair of integers $(m,n)$?
假设 $P = 2^m$ 和 $Q = 3^n$。以下哪个表达式对每对整数 $(m, n)$ 都等于 $12^{mn}$?
(A)
$P^2Q$
$P^2Q$
(B)
$P^nQ^m$
$P^nQ^m$
(C)
$P^nQ^{2m}$
$P^nQ^{2m}$
(D)
$P^{2m}Q^n$
$P^{2m}Q^n$
(E)
$P^{2n}Q^m$
$P^{2n}Q^m$
Answer
Correct choice: (E)
正确答案:(E)
Solution
We have $12^{mn} = (2\cdot 2\cdot 3)^{mn} = 2^{2mn} \cdot 3^{mn} = (2^m)^{2n} \cdot (3^n)^m = \boxed{{E.}\ P^{2n} Q^m}$.
我们有 $12^{mn} = (2\cdot 2\cdot 3)^{mn} = 2^{2mn} \cdot 3^{mn} = (2^m)^{2n} \cdot (3^n)^m = \boxed{\bold{E)} P^{2n} Q^m}$。
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