AMC12 2008 A
AMC12 2008 A · Q1
AMC12 2008 A · Q1. It mainly tests Rates (speed).
A bakery owner turns on his doughnut machine at $\text{8:30}\ {\small\text{AM}}$. At $\text{11:10}\ {\small\text{AM}}$ the machine has completed one third of the day's job. At what time will the doughnut machine complete the job?
一位面包店老板在 $\text{8:30}\ {\small\text{AM}}$ 打开他的甜甜圈机器。到 $\text{11:10}\ {\small\text{AM}}$ 时,机器已完成当天工作量的三分之一。甜甜圈机器将在什么时间完成全部工作?
(A)
1:50 pm
下午1:50
(B)
3:00 pm
下午3:00
(C)
3:30 pm
下午3:30
(D)
4:30 pm
下午4:30
(E)
5:50 pm
下午5:50
Answer
Correct choice: (D)
正确答案:(D)
Solution
The machine completes one-third of the job in $\text{11:10}-\text{8:30}=\text{2:40}$ hours. Thus, the entire job is completed in $3\cdot(\text{2:40})=\text{8:00}$ hours.
Since the machine was started at $\text{8:30 AM}$, the job will be finished $8$ hours later, at $\text{4:30 PM}$. The answer is $\mathrm{(D)}$.
Note: $\text{2:40}$ means $2$ hours and $40$ minutes. $3$ multiplied by this time interval is $8$ hours.
机器用时 $\text{11:10}-\text{8:30}=\text{2:40}$ 小时完成了工作的三分之一。因此,完成全部工作需要 $3\cdot(\text{2:40})=\text{8:00}$ 小时。
由于机器在 $\text{8:30 AM}$ 开始工作,$8$ 小时后完成,即在 $\text{4:30 PM}$。答案是 $\mathrm{(D)}$。
注:$\text{2:40}$ 表示 $2$ 小时 $40$ 分钟。将该时间间隔乘以 $3$ 得到 $8$ 小时。
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