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AMC12 2004 A

AMC12 2004 A · Q3

AMC12 2004 A · Q3. It mainly tests Linear equations.

For how many ordered pairs of positive integers $(x,y)$ is $x + 2y = 100$?
有多少对正整数的有序对 $(x,y)$ 满足 $x + 2y = 100$?
(A) 33 33
(B) 49 49
(C) 50 50
(D) 99 99
(E) 100 100
Answer
Correct choice: (B)
正确答案:(B)
Solution
Every integer value of $y$ leads to an integer solution for $x$ Since $y$ must be positive, $y\geq 1$ Also, $y = \frac{100-x}{2}$ Since $x$ must be positive, $y < 50$ $1 \leq y < 50$ This leaves $49$ values for y, which mean there are $49$ solutions to the equation $\Rightarrow \mathrm{(B)}$
每个整数 $y$ 的取值都会对应一个整数解 $x$。 由于 $y$ 必须为正整数,$y\geq 1$。 又有 $y = \frac{100-x}{2}$。 由于 $x$ 必须为正整数,$y < 50$。 因此 $1 \leq y < 50$。 这给出 $49$ 个 $y$ 的取值,因此该方程共有 $49$ 个解 $\Rightarrow \mathrm{(B)}$。
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