AMC12 2004 A
AMC12 2004 A · Q3
AMC12 2004 A · Q3. It mainly tests Linear equations.
For how many ordered pairs of positive integers $(x,y)$ is $x + 2y = 100$?
有多少对正整数的有序对 $(x,y)$ 满足 $x + 2y = 100$?
(A)
33
33
(B)
49
49
(C)
50
50
(D)
99
99
(E)
100
100
Answer
Correct choice: (B)
正确答案:(B)
Solution
Every integer value of $y$ leads to an integer solution for $x$
Since $y$ must be positive, $y\geq 1$
Also, $y = \frac{100-x}{2}$
Since $x$ must be positive, $y < 50$
$1 \leq y < 50$
This leaves $49$ values for y, which mean there are $49$ solutions to the equation $\Rightarrow \mathrm{(B)}$
每个整数 $y$ 的取值都会对应一个整数解 $x$。
由于 $y$ 必须为正整数,$y\geq 1$。
又有 $y = \frac{100-x}{2}$。
由于 $x$ 必须为正整数,$y < 50$。
因此 $1 \leq y < 50$。
这给出 $49$ 个 $y$ 的取值,因此该方程共有 $49$ 个解 $\Rightarrow \mathrm{(B)}$。
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