AMC12 2002 B
AMC12 2002 B · Q2
AMC12 2002 B · Q2. It mainly tests Manipulating equations.
What is the value of $(3x - 2)(4x + 1) - (3x - 2)4x + 1$ when $x=4$?
当 $x=4$ 时,$(3x - 2)(4x + 1) - (3x - 2)4x + 1$ 的值是多少?
(A)
0
0
(B)
1
1
(C)
10
10
(D)
11
11
(E)
12
12
Answer
Correct choice: (D)
正确答案:(D)
Solution
By the distributive property,
\[(3x-2)[(4x+1)-4x] + 1 = 3x-2 + 1 = 3x-1 = 3(4) - 1 = \boxed{\mathrm{(D)}\ 11}\].
由分配律,
\[(3x-2)[(4x+1)-4x] + 1 = 3x-2 + 1 = 3x-1 = 3(4) - 1 = \boxed{\mathrm{(D)}\ 11}\].
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