AMC10 2022 A
AMC10 2022 A · Q4
AMC10 2022 A · Q4. It mainly tests Unit conversion.
In some countries, automobile fuel efficiency is measured in liters per $100$ kilometers while other countries use miles per gallon. Suppose that 1 kilometer equals $m$ miles, and $1$ gallon equals $l$ liters. Which of the following gives the fuel efficiency in liters per $100$ kilometers for a car that gets $x$ miles per gallon?
在一些国家,汽车燃油效率以每 $100$ 公里的升数衡量,而其他国家使用每加仑英里数。假设 $1$ 公里的英里数为 $m$,$1$ 加仑的升数为 $l$。以下哪项给出了每加仑 $x$ 英里的汽车每 $100$ 公里的燃油效率(升数)?
(A)
\frac{x}{100lm}
\frac{x}{100lm}
(B)
\frac{xlm}{100}
\frac{xlm}{100}
(C)
\frac{lm}{100x}
\frac{lm}{100x}
(D)
\frac{100}{xlm}
\frac{100}{xlm}
(E)
\frac{100lm}{x}
\frac{100lm}{x}
Answer
Correct choice: (E)
正确答案:(E)
Solution
The formula for fuel efficiency is \[\frac{\text{Distance}}{\text{Gas Consumption}}.\]
Note that $1$ mile equals $\frac 1m$ kilometers. We have \[\frac{x\text{ miles}}{1\text{ gallon}} = \frac{\frac{x}{m}\text{ kilometers}}{l\text{ liters}} = \frac{1\text{ kilometer}}{\frac{lm}{x}\text{ liters}} = \frac{100\text{ kilometers}}{\frac{100lm}{x}\text{ liters}}.\]
Therefore, the answer is $\boxed{\textbf{(E) } \frac{100lm}{x}}.$
燃油效率的公式是 \[\frac{\text{距离}}{\text{油耗}}.\]
注意 $1$ 英里等于 $\frac 1m$ 公里。我们有 \[\frac{x\text{ miles}}{1\text{ gallon}} = \frac{\frac{x}{m}\text{ kilometers}}{l\text{ liters}} = \frac{1\text{ kilometer}}{\frac{lm}{x}\text{ liters}} = \frac{100\text{ kilometers}}{\frac{100lm}{x}\text{ liters}}.\]
因此,答案是 $\boxed{\textbf{(E) } \frac{100lm}{x}}$。
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